Please help me with this small php line
from:

Hello guys,

Maybe someone can help me with this small peace of code

With the code below Im showing the twitter url:

PHP:

Example: https://twitter.com/namehere

But I dont want to show the url, I want to show an image with a link.
I know that I can use this code:


Code (markup):

Please help me with this small php line

Poster :
Divvy